It should suffice to check out what happens (code-wise) if one of the "players" has only one square left. Does the "winning" player have a chance to hit that square and conquer it? Or does the program immediately register a collision for the "losing" player, who goes back to two squares?
I don't believe an end is possible. As one player's territory sprinks, it should quite naturally follow that it will have less travel time, hence more collisions.
