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SlyShy
on July 18, 2013
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Hyperloop: riding sound’s density peak to exploit ...
Kinetic energy = 1/2 m * v^2. Hyperloop trains wouldn't have "much" less energy, because the scaling factor on velocity is so high that your savings on train weight don't mean much.
You are right that it would take less power.
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You are right that it would take less power.