> I do speak German, I know how Freud is pronounced and I will pronounce it as it should be pronounced when speaking German, but when speaking English, it is Frood for me.
That... isn't the normal English pronunciation. The English pronunciation would rhyme with "joyed", if "joy" were a verb.
/'sɪg.mənd fɹɔɪd/
There are some other big names where the same vowel sequence isn't recognized: Euler (usually pronounced with /ɔɪ/) and von Neumann (not so much).
Euler suffers from beginning with the "eu", which makes it look more Greek.
> There are some other big names where the same vowel sequence isn't recognized: Euler (usually pronounced with /ɔɪ/) and von Neumann (not so much).
I always have trouble finding a reference for the sounds corresponding to IPA symbols, so I'm not sure what you're claiming for the pronunciation of either of those. But, at least among the mostly American mathematicians I know, the 'eu' in 'Euler' and 'von Neumann' are usually pronounced the same way we pronounce the same way we pronounce the 'eu' in 'Freud' (which I agree is essentially how I'd pronounce the 'oy' in 'joyed').
OK, thanks; that does make the claimed pronunciation clear. Still, I have literally never heard a mathematician pronounce the name that way (or Euler's in the analogous way).
That... isn't the normal English pronunciation. The English pronunciation would rhyme with "joyed", if "joy" were a verb.
/'sɪg.mənd fɹɔɪd/
There are some other big names where the same vowel sequence isn't recognized: Euler (usually pronounced with /ɔɪ/) and von Neumann (not so much).
Euler suffers from beginning with the "eu", which makes it look more Greek.