for 10^5, to get the same collision probability (~2 \* exp(-10)), you would just...

		sweezyjeezy on Jan 3, 2025 \| parent \| context \| favorite \| on: Can LLMs write better code if you keep asking them... for 10^5, to get the same collision probability (~2 * exp(-10)), you would just need to compute the 10 maximum/minimum candidates and check against those.