Hacker Newsnew | past | comments | ask | show | jobs | submitlogin

Yes. You can also take the log of the reciprocal probability (or "luck") and then you don't need the negative sign. This value is the expected number of trials you would need for the outcome to occur once. I find this presentation a bit more intuitive. See also Boltzmann entropy S = k log W which takes this form.


Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: