It is important to differentiate terminology here. According to DDG (which closely aligns with Google's results) the case fatality rate, the ratio of deaths to confirmed case, is 3.5%. For the death rate, the ratio of deaths relative to population size, is 0.01%.
Confirmed Cases: 21,991,954
Deaths: 777,018
World Pop.: ~7,800,000,000
Case Fatality Rate = Deaths/Confirmed Cases = ~3.5%
It would be ridiculous to assume the Deaths/World Population figure is the risk for yourself.
That's similar to claiming that, because only 93% of all humans ever born have died so far, your risk of dying is 93%. It may be mathematically sound, but completely ignores the context of the problem: That for the living/not-yet-infected the result is still outstanding.
This is an interesting point. I was recently working on research for how to apply model predictive control theory to TCP congestion control. We basically wanted to minimize latency while maximizing throughput. One of the challenges was that, while we could match latency and throughput set-points if known apriori, actually determining what the set-points should be was very difficult.
Here's an early paper on it https://arxiv.org/abs/2002.09825.
Note that if some of our control theory concepts seem a bit screwy, it's because we come from networking, not control theory :).
You're right about the velocity, but the impact force really depends on the properties of the material one lands on.
First consider that our kinetic energy is
K = mv^2/2
Additionally is the material has a spring constant k, then the force that results when the material deforms by x amount is
F(x) = kx
If we let d be the max distance the material, then we can integrate over the force to get the energy absorbed, which is equal to the kinetic energy.
int_0^d F(x) dx = K
kd^2/2 = mv^2/2
Now there are two ways the impact could work. Imagine we have a really thick crash pad, then we consider it to deform without limit and have a constant k, giving
d = sqrt(mv^2/k)
F_max = F(d) = v sqrt(mk)
But what about a helmet? It can only over it's thickness, at which point your head is basically in contact with the concrete. Thus, we have a constant deformation distance d, and get
k = mv^2/d^2
F(d) = mv^2/d
As we can see, depending on how we consider it we get either a force of sqrt(10) or 10 times the original amount. I probably failed to take into account something that someone who knew more about materials could point out.
tl;dr it's complicated because impact force does not necessarily scale linearly with velocity.
update: so after some conversation with others. It seems that head on concrete is better modeled by a constant d. So a drop of 10 times the height results in 10 times the force.
Confirmed Cases: 21,991,954
Deaths: 777,018
World Pop.: ~7,800,000,000
Case Fatality Rate = Deaths/Confirmed Cases = ~3.5%
Death Rate = Deaths/World Pop. = ~0.01%